Like any complex tool, the computer can be understood on several levels. For example, it's entirely possible to learn to drive an automobile without having the slightest idea of how it works. The analogy with computers is that it's relatively easy to learn how to use a word processor without having any notion of how such programs work. On the other hand, programming is much more closely analogous to designing an automobile than it is to driving one; therefore, we're going to have to go into some detail about the internal workings of a computer, not at the level of electronic components, but at the lowest level important to a Java programmer. This is a book on learning to program in Java, not on how a computer works. Therefore, it might seem better to start there and eliminate this detour, and indeed many (perhaps most) books on Java do exactly that. However, in working out in detail how I'm going to explain Java to you, I've come to the conclusion that it would be virtually impossible to explain why certain features of the language exist and how they actually work, without your understanding how they relate to the underlying computer hardware.
I haven't come to this position by pure logical deduction, either. In fact, I've worked backward from the concepts that you will need to know to program in Java to the specific underlying information that you will have to understand first. I'm thinking in particular of one specific concept, the reference, which is supposed to be extremely difficult for a beginning programmer in Java to grasp. With the approach we're taking, you shouldn't have much trouble understanding this concept by the time you get to it in Chapter inventor.htm; it's noted as such in the discussion there. I'd be interested to know how you find my explanation there, given the background that you'll have by that point; don't hesitate to e-mail me about this topic (or any other, for that matter).
On the other hand, if you're an experienced programmer, a lot of this will be just review for you. Nonetheless, it can't hurt to go over the basics one more time before diving into the ideas and techniques that make Java different from other languages.
Now let's begin with some definitions and objectives for this chapter.
A digit is one of the characters used in any positional number system to represent all numbers starting at 0 and ending at one less than the base of the number system. In the decimal system, there are ten digits, 0-9, and in the hexadecimal system there are sixteen digits, 0-9 and a-f.
A binary number system is one that uses only two digits, 0 and 1.
A hexadecimal number system is one that uses 16 digits, 0-9 and a-f.
A variable is a programming construct that represents a specific item of data that we wish to keep track of in a program. Some examples are the weight of a pumpkin or the number of cartons of milk in the inventory of a store.
By the end of this chapter, you should:
First we'll need to expand on the definition of hardware. As noted earlier, hardware means the physical components of a computer, the ones you can touch.^{1} Examples are the monitor, the keyboard, the printer, and all of the interesting electronic and electromechanical components inside the case of your computer.^{2} Right now we're concerned with the Java programmer's view of the hardware. The hardware components of a computer with which you'll be primarily concerned are the disk, RAM (short for Random Access Memory), and the CPU (short for Central Processing Unit).^{3} We'll take up each of these topics in turn.
When you sit down at your computer in the morning, before you turn it on, where are the programs you're going to run? To make this more specific, suppose you're going to use a word processor to revise a letter you wrote yesterday before you turned the computer off. Where is the letter, and where is the word processing program?
You probably know the answer to this question: They are stored on a disk inside the case of your computer.^{4} Disks use magnetic recording media, much like the material used to record speech and music on cassette tapes, to store information in a way that will not be lost when the power is turned off. How exactly is this information (which may be either executable programs or data such as word processing documents) stored?
We don't have to go into excruciating detail on the storage mechanism, but it is important to understand some of its characteristics. A disk consists of one or more circular platters, which are extremely flat and smooth pieces of metal or glass covered with a material that can be very rapidly and accurately magnetized in either of two directions, "north" and "south". To store large amounts of data, each platter is divided into many millions of small regions, each of which can be magnetized in either direction independent of the other regions. The magnetization is detected and modified by recording heads, similar in principle to those used in tape cassette decks. However, in contrast to the cassette heads, which make contact with the tape while they are recording or playing back music or speech, the disk heads "fly" a few millionths of an inch away from the platters, which rotate at very high velocity.^{5} The separately magnetizable regions used to store information are arranged in groups called sectors, which are in turn arranged in concentric circles called tracks. All tracks on one side of a given platter (a recording surface) can be accessed by a recording head dedicated to that recording surface; each sector is used to store some number of bytes of the data, generally a few hundred to a few thousand. "Byte" is a coined word meaning a group of 8 binary digits, or bits for short.^{6} You may wonder why the data aren't stored in the more familiar decimal system, which of course uses the digits from 0 through 9. This is not an arbitrary decision; on the contrary, there are a couple of very good reasons that data on a disk are stored using the binary system, in which each digit has only two possible states, 0 and 1. One of these reasons is that it's a lot easier to determine reliably whether a particular area on a disk is magnetized "north" or "south" than it is to determine 1 of 10 possible levels of magnetization. Another reason is that the binary system is also the natural system for data storage using electronic circuitry, which is used to store data in the rest of the computer.
Although magnetic storage devices have been around in one form or another since the very early days of computing, the advances in technology just in the last dozen years have been staggering. To comprehend just how large these advances have been, we need to define the term used to describe storage capacities: the Megabyte. The standard engineering meaning of Mega is "multiply by one million", which would make a Megabyte equal to one million (1,000,000) bytes. As we have just seen, however, the natural number system in the computer field is binary. Therefore, "one Megabyte" is often used instead to specify the nearest "round" number in the binary system, which is 2^20 (2 to the 20th power), or 1,048,576 bytes.^{7} This wasn't obvious to Susan, so I explained it some more, as you can see here:
Susan: Just how important is it to really understand that the Megabyte is 2^20 (1,048,576) bytes? I know that a meg is not really a meg; that is, it's more than a million. But I don't understand 2^20, so is it enough to just take your word on this and not get bogged down as to why I didn't go any further than plane geometry in high school? You see, it makes me worry and upsets me that I don't understand how you "round" a binary number.Steve: The ^ symbol is a common way of saying "to the power of", so 2^20 would be 2 to the power of 20; that is, twenty 2s multiplied together. This is a "round" number in binary just as 10 * 10 * 10 (1000) is a "round" number in decimal.
With that detail out of the way, we can see just how far we've come in a short period of time. In 1985, I purchased a 20 Megabyte disk for $900 ($45 per Megabyte); its access time, which measures how long it takes to retrieve data, was approximately 100 milliseconds (milli = 1/1000, so a millisecond is one thousandth of a second). In April 1997, a 6510 Megabyte disk cost as little as $449, or approximately 7 cents per Megabyte; in addition to delivering 650 times as much storage per dollar, this disk had an access time of 14 milliseconds, which is approximately 7 times as fast as the old disk. Of course, this significantly understates the amount of progress in technology in both economic and technical terms. For one thing, a 1997 dollar is worth considerably less than a 1985 dollar. In addition, the new drive is superior in every other measure as well: It is much smaller than the old one, consumes much less power, and has many times the projected reliability of the old drive.
This tremendous increase in performance and price has prevented the long-predicted demise of disk drives in favor of new technology. However, the inherent speed limitations of disks still require us to restrict their role to the storage and retrieval of data for which we can afford to wait a relatively long time.
You see, while 14 milliseconds isn't very long by human standards, it is a long time indeed to a modern computer. This will become more evident as we examine the next essential component of the computer, the RAM.
The working storage of the computer, where data and programs are stored while we're using them, is called RAM, which is an acronym for Random Access Memory.^{8} For example, your word processor is stored in RAM while you're using it. The document you're working on is likely to be there as well unless it's too large to fit all at once, in which case parts of it will be retrieved from the disk as needed. Since we have already seen that both the word processor and the document are stored on the disk in the first place, why not leave them there and use them in place, rather than copying them into RAM?
The answer, in a word, is speed. RAM is physically composed of millions of microscopic switches on a small piece of silicon known as a chip: a 4 Megabit RAM chip has approximately four million of them.^{9} Each of these switches can be either on or off; we consider a switch that is "on" to be storing a 1, and a switch that is "off" to be storing a 0. Just as in storing information on a disk, where it was easier to magnetize a region in either of two directions, it's a lot easier to make a switch that can be turned on or off reliably and quickly than one that can be set to any value from 0 to 9 reliably and quickly. This is particularly important when you're manufacturing millions of them on a silicon chip the size of your fingernail.
A main difference between disk and RAM is what steps are needed to access different areas of storage. In the case of the disk, the head has to be moved to the right track (an operation known as a seek), and then we have to wait for the platter to spin so that the region we want to access is under the head (called rotational delay). On the other hand, with RAM, the entire process is electronic; we can read or write any byte immediately, as long as we know which byte we want. To specify a given byte, we have to supply a unique number called its memory address or just address for short.
What is an address good for? Let's see how my discussion with Susan on this topic started.
Susan: About memory addresses: Are you saying that each little itty bitty tiny byte of RAM is a separate address? Well, this is a little hard to imagine.In case the notion of an address of a byte of memory on a piece of silicon is too abstract, it might help to think of an address as a set of directions as to how to find the byte being addressed, much like directions to someone's house. For example, "Go three streets down, then turn left. It's the second house on the right". With such directions, the house number wouldn't need to be written on the house. Similarly, the memory storage areas in RAM are addressed by position; you can think of the address as telling the hardware which street and house you want, by giving directions similar in concept to the preceding example. Therefore, it's not necessary to encode the addresses into the RAM explicitly.Steve: Actually, each byte of RAM has a separate address, which doesn't change, and a value, which does.
Susan wanted a better picture of this somewhat abstract idea.
Susan: Where are the bytes on the RAM, and what do they look like?Since it has no moving parts, storing and retrieving data in RAM is much faster than waiting for the mechanical motion of a disk platter turning.^{10} As we've just seen, disk access times are measured in milliseconds, or thousandths of a second. RAM access times, however, are measured in nanoseconds (abbreviated ns); nano means one billionth. In early 1997, a typical speed for RAM was 70 ns, which means that it is possible to read a given data item from RAM about 200,000 times as quickly as from a disk with an access time of 14 milliseconds. In that case, why not use disks only for permanent storage, and read everything into RAM in the morning when we turn on the machine?Steve: Each byte corresponds to a microscopic region of the RAM chip. As to what they look like, have you ever seen a printed circuit board such as the ones inside your computer? Imagine the lines on that circuit board reduced thousands of times in size to microscopic dimensions, and you'll have an idea of what a RAM chip looks like inside.
The reason is cost. In early 1997, the cost of 16 Megabytes of RAM was approximately $80. For that same amount of money, you could have bought over 1100 Megabytes of disk space!^{11}! Therefore, we must reserve RAM for tasks where speed is all-important, such as running your word processing program and holding a letter while you're working on it. Also, since RAM is an electronic storage medium (rather than a magnetic one), it does not maintain its contents when the power is turned off. This means that if you had a power failure while working with data only in RAM, you would lose everything you had been doing.^{12} This is not merely a theoretical problem, by the way; if you don't remember to save what you're doing in your word processor once in a while, you might lose a whole day's work from a power outage of a few seconds.^{13} Before we get to how a program actually works, we need to develop a better picture of how RAM is used. As I've mentioned before, you can think of RAM as consisting of a large number of bytes, each of which has a unique identifier called an address. This address can be used to specify which byte we mean, so the program might specify that it wants to read the value in byte 148257, or change the value in byte 66666. Susan wanted to make sure she had the correct understanding of this topic.
Susan: Are the values changed in RAM depending on what program is loaded in it?This is all very well, but it doesn't answer the question of how we actually use the data in RAM. The answer is by means of variables, which represent specific items of data that we wish to keep track of in our programs, such as weights and numbers of items.Steve: Yes, and they also change while the program is executing. RAM is used to store both the program itself and the values it manipulates.
You can put something in a variable, and it will stay there until you store something else there; you can also look at it to find out what's in it. As you might expect, several types of variables are used to hold different kinds of data; the first ones we will look at are variables representing whole numbers (the so-called integer variables), which are a subset of the category called numeric variables. As this suggests, there are also variables that represent numbers that can have fractional parts. We'll look at these so-called floating-point variables briefly in a later chapter.
Different types of variables require different amounts of RAM to
store them, depending on the amount of data they contain; a very common
type of numeric variable, known as a short
, requires 16
bits (that is, 2 bytes) of RAM to hold any of 65536 different values,
from -32768 to 32767, including 0. These odd-looking numbers are the
result of using the binary system. To make this number system more
intelligible, I have written the following little fable.
Once upon a time, the Acme company had a factory that made golf carts. One day, Bob, the president of Acme, decided to add an odometer to the carts, so that the purchaser of the cart could estimate when to recharge the battery. To save money, Bob decided to buy the little numbered wheels for the odometers and have his employees put the odometers together. The minimum order was a thousand odometer wheels, which was more than he needed for his initial run of 50 odometers. When he got the wheels, however, he noticed that they were defective: Instead of the numbers 0-9, each wheel had only two numbers, 0 and 1. Of course, he was quite irritated by this error, and attempted to contact the company from which he had purchased the wheels, but it had closed down for a month for summer vacation. What was he to do until it reopened?
While he was fretting about this problem, the employee who had been assigned to the task of putting the odometers together from the wheels came up with a possible solution. This employee, Jim, came into Bob's office and said, "Bob, I have an idea. Since we have lots of orders for these odometer-equipped carts, maybe we can make an odometer with these funny wheels and tell the customers how to read the numbers on the odometer."
Bob was taken aback by this idea. "What do you mean, Jim? How can anyone read those screwy odometers?"
Jim had given this some thought. "Let's take a look at what one of these odometers, say with five wheels, can display. Obviously, it would start out reading 00000, just like a normal odometer. Then when one mile has elapsed, the right-most wheel turns to 1, so the whole display is 00001; again, this is no different from a normal odometer."
"Now we come to the tricky part. The right-most wheel goes back to 0, not having any more numbers to display, and pushes the `tens' wheel to 1; the whole number now reads 00010. Obviously, one more mile makes it 00011, which gives us the situation shown in the following diagram:
Normal odometer Funny odometer
00000 00000
00001 00001
00002 00010
00003 00011
Jim continued, "What's next? This time, the right-most wheel turns over again to 0, triggering the second wheel to its next position. At this point, however, the second wheel is already at its highest value, 1; therefore, it also turns over to 0 and increments the third wheel. It's not hard to follow this for a few more miles, as illustrated in Figure nextfew.
Normal odometer Funny odometer
00004 00100
00005 00101
00006 00110
00007 00111
Each wheel has two numbers, 0 and 1. So with one wheel, we have a total of two combinations. Two wheels can have either a 0 or a 1 for the first number, and the same for the second number, for a total of four combinations. With three wheels, the same analysis holds: 2 numbers for the first wheel * 2 for the second wheel * 2 for the third wheel = 8 possibilities in all; actually, they are the same 8 possibilities we saw in Figures firstfew and nextfew.
A pattern is beginning to develop: For each added wheel, we get twice as many possible combinations. To see how this continues, take a look at Figure howmany, which shows the count of combinations versus the number of wheels for all wheel counts up to 16 (i.e., 16-bit quantities).
Number of wheels Number of combinations^{14}
1 2
2 4
3 8
4 16
5 32
6 64
7 128
8 256
9 512
10 1024
11 2048
12 4096
13 8192
14 16384
15 32768
16 65536
which, according to his translation chart, was 16,375 miles. What could have gone wrong?
The next mile will turn the last digit back to 0, producing
What happens next? The last wheel turns back to 1, and triggers the second wheel to switch as well:
The next few "backward" numbers look like this:
As it happens, there is. It's called hexadecimal, which means "base 16". As a rule, the term hexadecimal is abbreviated to hex. Since there are 16 possible combinations of 4 bits (2*2*2*2), hexadecimal notation allows 4 bits of a binary number to be represented by one hex digit. Unfortunately, however, there are only 10 "normal" digits, 0-9.^{15} To represent a number in any base, you need as many different digit values as the base, so that any number less than the base can be represented by one digit. For example, in base 2, you need only two digits, 0 and 1. In base 8 (octal), you need eight digits, 0-7.^{16} So far, so good. But what about base 16? To use this base, we need 16 digits. Since only 10 numeric digits are available, hex notation needs a source for the other six digits. Because letters of the alphabet are available and familiar, the first six letters, a-f, were adopted for this service.^{17} Although the notion of a base 16 number system doesn't seem strange to people who are familiar with it, it can really throw someone who learned normal decimal arithmetic solely by rote, without understanding the concepts on which it is based. This topic of hexadecimal notation occupied Susan and me for quite awhile; here's some of the discussion we had about it:
Susan: I don't get this at all! What is the deal with the letters in the hex system? I guess it would be okay if 16 wasn't represented by 10!Now that we've seen how each hex digit corresponds exactly to a group of four binary digits, here's an exercise you can use to improve your understanding of this topic: Invent a random string of four binary digits and see where it is in Figure binhex. I guarantee it'll be there somewhere! Then look at the "hex" column and see what "digit" it corresponds to. There's nothing really mysterious about hex; since we have run out of digits after 9, we have to use letters to represent the numbers `ten', `eleven', `twelve', `thirteen', `fourteen', and `fifteen'.Steve: Well, there are only 10 "normal" digits, 0-9. To represent a number in any base, you need as many "digits" as the base, so that any number less than the base can be represented by one "digit". This is no problem with a base less than ten, such as octal, but what about base 16? To use this base we need 16 digits, 0-9 and a-f. One way to remember this is to imagine that the "hex" in "hexadecimal" stands for the six letters a-f and the "decimal" stands for the 10 digits 0-9.
Susan: OK, so a hex digit represents 16 bits? So then is hex equal to 2 bytes? According to the preceding, a hex digit is 4 bits.
Steve: Yes, a hex digit represents 4 bits. Let's try a new approach. First, let me define a new term, a hexit. That's short for "hex digit", just like "bit" is short for "binary digit". Now let's look at the answers to the following questions.
- How many numbers can be represented with no more than one decimal digit?
- How many numbers can be represented with no more than two decimal digits?
- How many numbers can be represented with no more than three decimal digits?
- How many numbers can be represented with no more than four decimal digits?
- How many numbers can be represented with no more than one bit?
- How many numbers can be represented with no more than two bits?
- How many numbers can be represented with no more than three bits?
- How many numbers can be represented with no more than four bits?
- How many numbers can be represented with no more than one hexit?
- How many numbers can be represented with no more than two hexits?
- How many numbers can be represented with no more than three hexits?
- How many numbers can be represented with no more than four hexits?
The answers are:
- 10
- 100
- 1000
- 10000
- 2
- 4
- 8
- 16
- 16
- 256
- 4096
- 65536
What do all these answers have in common? Let's look at the answers a little differently, in powers of 10, 2, and 16, respectively:
- 10 = 10^1
- 100 = 10^2
- 1000 = 10^3
- 10000 = 10^4
- 2 = 2^1
- 4 = 2^2
- 8 = 2^3
- 16 = 2^4
- 16 = 16^1
- 256 = 16^2
- 4096 = 16^3
- 65536 = 16^4
That is, a number that has one digit can represent "base" different values, where "base" is two, ten, or sixteen (in our examples). Every time we increase the size of the number by one more digit, we can represent "base" times as many possible different values, or in other words, we multiply the range of values that the number can represent by the base. Thus, a two-digit number can represent any of "base*base" values, a three-digit number can represent any of "base*base*base" values, and so on. That's the way positional number systems such as decimal, binary, and hex work. If you need a bigger number, you just add more digits.
Okay, so what does this have to do with hex? If you look at the above table, you'll see that 2^4 (16) is equal to 16^1. That means that 4 bits are exactly equivalent to one hexit in their ability to represent different numbers: Exactly 16 possible numbers can be represented by four bits, and exactly 16 possible numbers can be represented by one hexit.
This means that you can write one hexit wherever you would otherwise have to use four bits, as illustrated in Figure binhex.
4-bit value 1-hexit value
0000 0
0001 1
0010 2
0011 3
0100 4
0101 5
0110 6
0111 7
1000 8
1001 9
1010 a
1011 b
1100 c
1101 d
1110 e
1111 f
Binary to hex conversion table (Figure binhex)
Here's a table showing the correspondence between some decimal, hex, and binary numbers, with the values of each digit position in each number base indicated, and the calculation of the total of all of the bit values in the binary representation, as shown in Figure diffrep.
Decimal Hexadecimal Binary Sum of Binary
Place Values Place Values Place Values Digit Values
10 1 16 1 16 8 4 2 1
0 0 0 0 0 0 0 0 = 0 + 0 + 0 + 0 + 0
1 0 1 0 0 0 0 1 = 0 + 0 + 0 + 0 + 1
2 0 2 0 0 0 1 0 = 0 + 0 + 0 + 2 + 0
3 0 3 0 0 0 1 1 = 0 + 0 + 0 + 2 + 1
4 0 4 0 0 1 0 0 = 0 + 0 + 4 + 0 + 0
5 0 5 0 0 1 0 1 = 0 + 0 + 4 + 0 + 1
6 0 6 0 0 1 1 0 = 0 + 0 + 4 + 2 + 0
7 0 7 0 0 1 1 1 = 0 + 0 + 4 + 2 + 1
8 0 8 0 1 0 0 0 = 0 + 8 + 0 + 0 + 0
9 0 9 0 1 0 0 1 = 0 + 8 + 0 + 0 + 1
1 0 0 a 0 1 0 1 0 = 0 + 8 + 0 + 2 + 0
1 1 0 b 0 1 0 1 1 = 0 + 8 + 0 + 2 + 1
1 2 0 c 0 1 1 0 0 = 0 + 8 + 4 + 0 + 0
1 3 0 d 0 1 1 0 1 = 0 + 8 + 4 + 0 + 1
1 4 0 e 0 1 1 1 0 = 0 + 8 + 4 + 2 + 0
1 5 0 f 0 1 1 1 1 = 0 + 8 + 4 + 2 + 1
1 6 1 0 1 0 0 0 0 = 16 + 0 + 0 + 0 + 0
1 7 1 1 1 0 0 0 1 = 16 + 0 + 0 + 0 + 1
1 8 1 2 1 0 0 1 0 = 16 + 0 + 0 + 2 + 0
1 9 1 3 1 0 0 1 1 = 16 + 0 + 0 + 2 + 1
Susan had some more thoughts on the hexadecimal number system. Let's listen in.
Susan: I think you need to spend a little more time reviewing the hex system, like an entire chapter.<G> Well, I am getting the impression that we are going to be working with hex, so I am trying to concentrate my understanding on that instead of binary. I think this all moves a little too fast for me. I don't know what your other reviewers are saying but I just feel like I get a definition of a abstract concept, and the next thing I know I am supposed to be doing something with it, like make it work. Ha! I personally need to digest new concepts, I really need to think them over a bit, to take them in and absorb them. I just can't start working with it right away.As usual, I've complied with her request; the results are immediately ahead.
Here are some exercises that you can use to check your understanding of the binary and hexadecimal number systems.^{18} I've limited the examples to addition and subtraction, as that is all that you're ever likely to have to do in these number systems. These operations are exactly like their equivalents in the decimal system, except that as we have already seen, the hexadecimal system has six extra digits after 9: a, b, c, d, e, and f. We have to take these into account in our calculations: for example, adding 9 and 5, rather than producing 14, produces e.
x
is a short
,
currently holding the value 32767, or 7fff in hex. What is the result
of adding 1 to x
, in both decimal and hex? Answers to exercises can be found at the end of the chapter.
There's one point we haven't covered yet: how these variables are actually referred to and modified. The ultimate answer to that question is that every action in the computer is performed by another piece of hardware: the CPU (Central Processing Unit). Like RAM, it is physically composed of millions of microscopic transistors on a chip; however, the organization of these transistors in a CPU is much more complex than on a RAM chip, as the latter's functions are limited to the storage and retrieval of data. The CPU, on the other hand, is capable of performing dozens or hundreds of different fundamental operations called machine instructions, or just instructions for short. While each instruction performs a very simple function, the tremendous power of the computer lies in the fact that the CPU can perform (or execute) tens or hundreds of millions of these instructions per second.^{19} These instructions fall into a number of categories: instructions that perform arithmetic operations such as adding, subtracting, multiplying, and dividing; instructions that move information from one place to another in RAM; instructions that compare two quantities to help make a determination as to which instructions need to be executed next and instructions that implement that decision; and other, more specialized types of instructions.
With most languages, the programs you write are translated into machine instructions for a specific CPU. However, one of the design goals of Java was to allow the same translated program to work on any machine. To facilitate this task, the process of making your programs runnable works differently in Java: Instead of your programs being translated into a form designed to be executed on a specific CPU, they are translated into a form that can be executed on any CPU with the intervention of a special program called an interpreter. We'll go into how this works in great detail in the next chapter; for now, just keep in mind that Java programs aren't tied to a specific type of computer.
You've just been subjected to a barrage of information on how a computer works. Let's go over it again briefly before continuing.
Two main components of the computer hardware are of most significance to Java programmers: disk and RAM. Both of these store programs and data for use by Java programs.
Computers represent pieces of information (or data) as binary digits, universally referred to as bits. Each bit can have the value 0 or 1. The binary system is used instead of the more familiar decimal system because it is much easier to make devices that can store and retrieve 1 of 2 values than 1 of 10. Bits are grouped into sets of eight, called bytes.
The disk uses magnetic recording heads to store and retrieve groups of a few hundred bytes on rapidly spinning platters in a few milliseconds. The contents of the disk are not lost when the power is turned off, so it is suitable for more or less permanent storage of programs and data.
RAM, which is an acronym for Random Access Memory, is used to hold programs and data while they're in use. It is made of millions of microscopic transistors on a piece of silicon called a chip. Each bit is stored using a few of these transistors. RAM does not retain its contents when power is removed, so it is not good for permanent storage. However, any byte in a RAM chip can be accessed in about 70 nanoseconds (billionths of a second), which is hundreds of thousands of times as fast as accessing a disk. Each byte in a RAM chip can be independently stored and retrieved without affecting other bytes, by providing the unique memory address belonging to the byte you want to access.
The binary system is the most fundamental number system in the computer, but it is not very convenient for people, especially when dealing with large numbers. For this purpose, the hexadecimal number system is considerably more convenient, as the representations of large numbers are much shorter and easier to remember.
Unlike most other computer languages, Java was designed to allow the same program to be run on various kinds of computers, with the intervention of a special kind of program called an interpreter.
In this chapter, we've covered a lot of material on how a computer actually works. As you'll see, this background is essential if you're going to understand what really happens inside a program. In the next chapter, we'll get to the "real thing": how to write a program to make all this hardware do something useful.
Susan: Problem 1a. My answer is 38. Why? My own personal way of thinking: If a = 10, right? and if e = 14 and if 1 * 10 = 10 and if 2 * 14 = 28, then if you add 10 + 28 you get 38. So please inform me how you arrived at 48? I didn't bother with the rest of the problems. If I couldn't get the first one right, then what was the point?- Steve: Here's how you do this problem, with the letter "h" indicating a hex number:
- 10h(1 * 16) + ah(10 * 1)
- 20h(2 * 16) + eh(14 * 1)
- ------------------
- 30h(3 * 16) + 18h(24 * 1 = 1 * 16 + 8 * 1)
- Carry the 1 from the low digit to the high digit of the answer, to produce:
- 40h(4 * 16) + 8h(8 * 1), or 48 hex, which is the answer.
short
values is -32768 to +32767, with 0000h to 7fffh
being considered positive, and 8000h to ffffh considered negative.
You may have noticed that the terms RAM and ROM aren't symmetrical; why isn't RAM called RWM, Read-Write Memory? Because that's too hard to pronounce.
short
.
This is no coincidence; read on for the detailed explanation.